Question -
Answer -
Given:
The digits 1, 3, 3, 0
Total number of digits= 4
Digits of the sametype = 2
Total number of 4digit numbers = 4! / 2!
Where, zero cannot bethe first digit of the four digit numbers.
So, Total number of 3digit numbers = 3! / 2!
Total number ofNumbers = (4! / 2!) – (3! / 2!)
= [(4×3×2)/2] –[(3×2)/2]
= [4×3] – [3]
= 12 – 3
= 9
Hence, total number offour digit can be formed is 9.