Question -
Answer -
Let us assume thereare six seats.
In the first seat, anyone of six members can be seated, so the total number of possibilities is 6C1
In the second seat,any one of five members can be seated, so the total number of possibilitiesis 5C1 ways.
In the third seat, anyone of four members can be seated, so the total number of possibilitiesis 4C1 ways.
In the fourth seat,any one of three members can be seated, so the total number of possibilitiesis 3C1 ways.
In the fifth seat, anyone of two members can be seated, so the total number of possibilities is 2C1 ways.
In the sixth seat,only one remaining person can be seated, so the total number of possibilitiesis 1C1 ways.
Hence, the totalnumber of possible outcomes = 6C1 × 5C1 × 4C1 × 3C1 × 2C1 × 1C1 =6 × 5 × 4 × 3 × 2 × 1 = 720.