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Question -

In the given figure, if ∠ACB = 40°, ∠DPB = 120°, find ∠CBD.



Answer -

It is given that ∠ACB = 40° and ∠DPB = 120°
 
Construction: Join the point A and B
            (Angle in the same segment)
Now in △BDP△BDP we have

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