Question -
Answer -
We have to find 
and 
Construction: - O is centre and r is radius and given that chord is equal to radius of circle
Now in 
we have
AO = OB = BA ( It is given that chord is equal to radius of circle)
So, is an equilateral triangle So, ∠AOB=2∠ADB∠AOB=2∠ADB (The angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle)
Then
So
Therefore,
and 
Hence, the angle subtended by the chord at a point on the minor arc is 150° and also at a point on the major arc is 30°.