Question -
Answer -
Let us make the tableof the given data and append other columns after calculations.
| Xi | fi | c.f. | |xi – M| | fi |xi – M| |
| 15 | 3 | 3 | 15 | 45 |
| 21 | 5 | 8 | 9 | 45 |
| 27 | 6 | 14 | 3 | 18 |
| 30 | 7 | 21 | 0 | 0 |
| 35 | 8 | 29 | 5 | 40 |
Now, N = 29, which isodd.
So 29/2 = 14.5
The cumulativefrequency greater than 14.5 is 21, for which the corresponding observation is30.
Then,
Median = (15th observation+ 16th observation)/2
= (30 + 30)/2
= 60/2
= 30
So, the absolutevalues of the respective deviations from the median, i.e., |xi –M| are shown in the table.
