The Total solution for NCERT class 6-12
Let us consider F1 =86o F
And F2 =95o
We know, F = 9/5C + 32
F1 =9/5 C1 + 32
F1 –32 = 9/5 C1
C1 =5/9 (F1 – 32)
= 5/9 (86 – 32)
= 5/9 (54)
= 5 × 6
= 30o C
Now,
F2 =9/5 C2 + 32
F2 –32 = 9/5 C2
C2 =5/9 (F2 – 32)
= 5/9 (95 – 32)
= 5/9 (63)
= 5 × 7
= 35o C
∴ The range oftemperature of the solution in degree Celsius is 30° C and 35° C.