The Total solution for NCERT class 6-12
Let us consider C1 =30o C
And C2 =35o
We know, F = 9/5C + 32
F1 =9/5 C1 + 32
= 9/5 × 30 + 32
= 9 × 6 + 32
= 54 + 32
= 86o F
Now,
F2 =9/5 C2 + 32
= 9/5 × 35 + 32
= 9 × 7 + 32
= 63 + 32
= 95o F
∴ The range oftemperature of the solution in degree Fahrenheit is 86° F and 95° F.