Question -
Answer -
is given with
AD is any line from A to BC intersecting BE in H.
P,Q and R respectively are the mid-points of AH,AB and BC.
We need to prove that
Let us extend QP to meet AC at M.
In
, R and Q are the mid-points of BC and AB respectively.Theorem states, the line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it.
Therefore, we get:
…… (i) Similarly, in
,
…… (ii)
From (i) and (ii),we get:
and We get,
is a parallelogram.Also,
Therefore,
is a rectangle.Thus,
Or,
Hence proved.