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Question -

17x2 – 8x + 1 = 0



Answer -

Given: 17x2 –8x + 1 = 0

We shall applydiscriminant rule,

Where, x = (-b ±√(b2 – 4ac))/2a

Here, a = 17, b = -8,c = 1

So,

x = (-(-8) ±√(-82 – 4(17)(1)))/ 2(17)

= (8 ± √(64-68))/34

= (8 ± √(-4))/34

= (8 ± √4(-1))/34

We have i2 =–1

By substituting –1 = i2 inthe above equation, we get

x = (8 ± √(2i)2)/34

= (8 ± 2i)/34

= 2(4±i)/34

= (4±i)/17

x = 4/17 ± i/17

The roots of thegiven equation are 4/17 ± i/17

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