Question -
Answer -
Given : In тИЖABC, AB = AC the bisectors of тИаB and тИаC intersect at O. M is any point on BO produced.
┬а
To prove : тИаMOC = тИаABC
Proof: In тИЖABC, AB = BC
тИ┤ тИаC = тИаB
тИ╡ OB and OC are the bisectors of тИаB and тИаC
тИ┤ тИа1 =тИа2 =┬а
┬атИаB Now in тИаOBC,
Ext. тИаMOC = Interior opposite angles тИа1 + тИа2
= тИа1 + тИа1 = 2тИа1 = тИаB
Hence тИаMOC = тИаABC