The Total solution for NCERT class 6-12
A park, in the shape of a quadrilateral ABCD, has ∠C = 90°, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. Howmuch area does it occupy?
Let us joinBD.
In ΔBCD, applying Pythagoras theorem,
BD2 = BC2 +CD2
= (12)2 +(5)2
= 144 + 25
BD2 = 169
BD = 13 m
For ΔABD,
By Heron’sformula,
Area of triangle
Area of thepark = Area of ΔABD + Area of ΔBCD
= 35.496 + 30 m2 = 65.496 m2 =65.5 m2 (approximately)