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Question -

In a circle ofradius 21 cm, an arc subtends an angle of 60┬░ at the centre.┬а



Answer -

Find:

(i) the length of the arc

(ii) area of the sector formed by the arc

(iii) area of the segment formed by the corresponding chord

Solution

Given,

Radius = 21 cm

╬╕ = 60┬░

(i)┬аLength of an arc = ╬╕/360┬░├ЧCircumference(2╧Аr)

тИ┤ Length of an arc AB = (60┬░/360┬░)├Ч2├Ч(22/7)├Ч21

= (1/6)├Ч2├Ч(22/7)├Ч21

Or Arc AB Length = 22cm

(ii)┬аIt is given that the angle subtend by the arc = 60┬░

So, area of the sector making an angle of 60┬░= (60┬░/360┬░)├Ч╧А r2┬аcm2

= 441/6├Ч22/7 cm2

Or, the area of the sector formed by the arcAPB is 231 cm2

(iii)┬аArea of segment APB = Area of sector OAPB тАУ Area of ╬ФOAB

Since the two arms of the triangle are theradii of the circle and thus are equal, and one angle is 60┬░, ╬ФOAB is anequilateral triangle. So, its area will be тИЪ3/4├Чa2┬аsq. Units.

Area of segment APB = 231-(тИЪ3/4)├Ч(OA)2

= 231-(тИЪ3/4)├Ч212

Or, Area of segment APB = [231-(441├ЧтИЪ3)/4] cm2

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