Question -
Answer -
The equation of a circle with centre (h, k)and radius r is given as
(x┬н тАУ h)2 + (y ┬нтАУ k)2 = r2
It is given that centre (h, k)= (тАУ2, 3) and radius (r) = 4.
Therefore, the equation ofthe circle is
(x + 2)2 + (y тАУ3)2 = (4)2
x2 + 4x + 4+ y2 тАУ 6y + 9 = 16
x2 + y2 + 4x тАУ 6y тАУ3 = 0