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Question -

In a ∆ABC, ∠A = 50° and BC is produced to a point D. If the bisectors of ∠ABC and ∠ACD meet at E, then ∠E =
(a) 25°
(b) 50°
(c) 100°
(d) 75°



Answer -

In ∆ABC, ∠A = 50°
BC is produced
 
Bisectors of ∠ABC and ∠ACD meet at ∠E
∴ ∠E =   ∠A =   x 50° = 25° (a)

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