Question -
Answer -
The vertices of the given triangle are (4, 4), (3, 5) and (–1,–1).
The slope (m) of the line non-vertical line passing through thepoint (x1, y1) and
(x2, y2) is given by m = (y2 – y1)/(x2 – x1) where, x ≠ x1
So, the slope of the line AB (m1) = (5-4)/(3-4) = 1/-1 = -1
the slope of the line BC (m2) = (-1-5)/(-1-3) = -6/-4 = 3/2
the slope of the line CA (m3) = (4+1)/(4+1) = 5/5 = 1
It is observed that, m1.m3 =-1.1 = -1
Hence, the lines AB and CA are perpendicular to each other
∴ giventriangle is right-angled at A (4, 4)
And the vertices of the right-angled ∆ are (4, 4), (3, 5) and(-1, -1)