Question -
Answer -
Let us consider if the given points A (h, 0), B (a, b) and C (0,k) lie on a line
Then, slope of AB = slope of BC
(b – 0)/(a – h) = (k – b)/(0 – a)
let us simplify we get,
-ab = (k-b) (a-h)
-ab = ka- kh –ab +bh
ka +bh = kh
Divide both the sides by kh we get,
ka/kh + bh/kh = kh/kh
a/h + b/k = 1
Hence proved.