The Total solution for NCERT class 6-12
In a ∆ABC,if a = 5, b = 6 and C = 60o, show that its area is (15√3)/2 sq.units.
Given:
In a ∆ABC, a = 5, b = 6 and C = 60o
By using the formula,
Area of ∆ABC = 1/2 ab sin θ where, a and b are thelengths of the sides of a triangle and θ is the angle between sides.
So,
Area of ∆ABC = 1/2 ab sin θ
= 1/2 × 5 × 6 × sin 60o
= 30/2 × √3/2
= (15√3)/2 sq. units
Hence proved.