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Question -

In the figure, if AB || CD, then x =
(a) 100°
(b) 105°
(c) 110°
(d) 115°



Answer -

In the figure, AB || CD
Through P, draw PQ || AB or CD
 
∠A + ∠1 = 180° (Co-interior angles)
⇒ 132° + ∠1 = 180°
⇒ ∠1 = 180°- 132° = 48°
∴ ∠2 = 148° – ∠1 = 148° – 48° = 100°
∵ DQ || CP
∴ ∠2 = x (Corresponding angles)
∴ x = 100° (a)

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