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Question -

What value ofy would make AOB, a line in the figure, if ∠AOC = 4y and ∠BOC = (6y + 30).



Answer -

In the figure,
AOB is a line if
∠AOC + ∠BOC = 180°
⇒ 6y + 30° + 4y= 180°
⇒ 10y= 180°-30°= 150°
150°
⇒ y == 15°
∴ y = 15°

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